画像 3/2x-5/3y=-2 x/3 y/2=13/6 217556

NCERT SOLUTIONS Real Numbers Class 10 Real Numbers Mathematics QUESTIONS 1 Use Euclid's division algorithm to find the HCF of (i) 135 and 225 (ii) 196 and 3 (iii) 867 and 255 2 Show that any positive odd integer is of the form 6q 1,X/3 y/2 = 13/6 Ex 34, 1 (Elimination) Solve the following pair of linear equations by the elimination method and the substitution method (i) x y = 5 and 2x – 3y = 4 x y = 5 2x – 3y = 4 Multiplying equation (1) by 2 2(x y) = 2 × 5 2x 2y = 10 Solving

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3/2x-5/3y=-2 x/3 y/2=13/6

3/2x-5/3y=-2 x/3 y/2=13/6-Askedin Mathematicsby Samantha(3kpoints) Solve the following pairs of linear equations by the substitution method 3x/2 5y/3 = 2, x/3 y/2 = 13/6 pair of linear equations in two variables cbse class103/2x – 5/3y = 2 (i) x/3 y/2 = 13/6 (ii) From equation (i), we get 9x – 10y = 12 x = 12 10y/9 (iii) Putting this value in equation (ii), we get wordimage 2 Solve 2x 3y = 11 and 2x – 4y = – 24 and hence find the value of 'm' for which y = mx 3 Answer

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 Click here 👆 to get an answer to your question ️ 3/2x5/3y=2;x/3y/2=13/6 solve by substitution methodQuestion 1 Solve the following pair of linear equations by the substitution method (i) x y = 14 ;(vi) 3/2x 5/3y = 2 x/3 y/2 = 13/6 Answer 1 Method of elimination by substitution 1) Suppose the equation are a 1xb 1yc 1=0 a 2x b 2yc 2=0 2) Find the value of variable of either x or y in other variable term in first equation 3) Substitute the value of that variable in second equation 4) Now this is a linear equation in one variable Find

X – y = 4 (ii) s – t = 3 ;Download free PDF of best NCERT Solutions , Class 10, Math, CBSE Linear Equations in two variables All NCERT textbook questions have been solved by our expert teachers You can also get free sample papers, Notes, Important QuestionsS/3 t/2 = 6 (iii) 3x – y = 3 ;

 x/3 y/2 = 13/6 (2) Solve first equation 3/2 x 5/3 y = 2 Multiply by 6 to remove all denominator we get 9 x – 10 y = 12 9x = 12 10y Divide by 9 we get x = (12 10 y)/9 (3) plug this value in equation (2) we get MultiplyX/3y/2=13/6 Maths Pair of Linear Equations in Two Variables√3 x √8y = 0 (vi)3/2 x 5/3y = 2 ;

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9x – 3y = 9 (iv) 02x 03y = 13 ;Solve the following pair of linear equations by the substitution method (3x)/2 (5y)/3 = 2, x/yy/2 = 13/604x 05y = 23 (v)√2 x √3y = 0 ;

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X/3 y/2 = 13/16 From equation (I) we get 9x 10y = 12 X = 12 10y/9 Putting value of x in this equation12 10y/9 / 3 y/2 = 13/6 47y = 17 24 Y = 3 Putting value of yin this equation X = 12 10 x 3 /9 = 2 X = 2 and y = 3 Q2 Solve 2x 3y = 11 and 2x – 4y = 24 and hence find the value of 'm' for which y = mx 3 Solution 3/2x – 5/3y = 2;(x/3) (y/2) = (13/6) 3/2x – 5/3y = 2 (i) x/3 y/2 = 13 /6 (ii) From equation (i), we get 9x – 10y = 12 x = 12 10y/9 (iii) Putting this value in equation (ii), we get $ begin{equation} begin{array}{l} frac{frac{1210 y}{9}}{3}frac{y}{2}=frac{13}{6} \ frac{1210 y}{27}frac{y}{2}=frac{13}{6} \ frac{24 y27 y}{54}=frac{13}{6} end{array}

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